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Posted on 02-14-11 10:39 PM     Reply [Subscribe]
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Shoot out your problems...
Lets share and expand the knowledge.....!!!!



We are open to share on(any IT related stuffs) :

- Javascript/JQuery/Ajax
- Java,JSP,Servlets and Frameworks
- WebServices
- Unix, Linux, Webserver Administration


+ many more !!!!

 
Posted on 03-11-11 11:53 PM     [Snapshot: 2498]     Reply [Subscribe]
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Last edited: 12-Mar-11 09:47 PM

 
Posted on 03-13-11 10:59 PM     [Snapshot: 2580]     Reply [Subscribe]
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Last edited: 21-Mar-11 01:24 PM

 
Posted on 03-13-11 11:34 PM     [Snapshot: 2594]     Reply [Subscribe]
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are you expecting anything different than the solution by prankster?


 
Posted on 03-14-11 10:10 AM     [Snapshot: 2630]     Reply [Subscribe]
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@nepali8

prankster did it for you.
I meant the code explanation.

 
Posted on 03-14-11 10:13 AM     [Snapshot: 2633]     Reply [Subscribe]
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lol, I wonder why troy removed all his posts?
 
Posted on 03-14-11 11:01 AM     [Snapshot: 2652]     Reply [Subscribe]
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Posted on 03-14-11 12:11 PM     [Snapshot: 2668]     Reply [Subscribe]
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hi Guys!!!!!!!!!!!!!!!!!

@ default 061 and Ayus, as i am beginners learning c#,  it will be better for me if there's more explanation . 
 
Thank you guys


 
Posted on 03-14-11 12:46 PM     [Snapshot: 2676]     Reply [Subscribe]
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here is the pseudocode  by prankster with lil explanation,
double first[10] = {1.2,1.3,5.6.......................} // initialization of first array with 10 blocks ( 0 to 9 index)
double second[10] = {2.3, 4.2, 5.3,....................}//// initialization of second array with 10 blocks ( 0 to 9 index)

double product[10]; // declaration of third array that will store final result, it has 10 blocks too

for (int i=0;i<10;i++) //  value of 'i' starts from 0 and goes up to 9, when 'i' reaches 10 , condition i<10 fails so loop   terminates
{
    product[i] = first[i] * second[i]   //value stored at 'i' index of product = value of 'i' index of first array * value of 'i' index of second array

}


that for loop would be :
  product[0]=first[0]*second[0] = 1.2*2.3= ..
product[1]=first[1]*second[1]=1.3*4.2=..

and continues up to product[9]=first[9]*second[9]=....

What you can add:
Declare String before for loop : ex String result=" ";
Inside for loop , style the output for arraays and  concat it to the result :
ex,  result=result+"  "+ first[i]+"  * "+second[i]+" =" +product[i] + "\n" ;

// this will collect all your contents of array in one string , ie result

Now you can display result in one line using whatever is required, just display that string "result"


 
Posted on 03-18-11 10:16 AM     [Snapshot: 2744]     Reply [Subscribe]
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Sun.com, The 11th Oldest .com Domain, Exits Internet On June 1st

http://wwwery.com/12806-sun-com-shuts.html


 
Posted on 03-19-11 7:59 PM     [Snapshot: 2820]     Reply [Subscribe]
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Posted on 03-22-11 1:30 PM     [Snapshot: 2904]     Reply [Subscribe]
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 Hey guys!!!

Need some help in c sharp

How to write  a syntax to store the product of the two arrays in the third array?

thanks for help!!!!!!!!

 
Posted on 03-22-11 2:09 PM     [Snapshot: 2918]     Reply [Subscribe]
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 hi!!!!!!!!!
Need help guys!!!
C#

Produce a display using messagebox class that show contents of all three arrays.

thanks!!

 
Posted on 03-22-11 2:30 PM     [Snapshot: 2928]     Reply [Subscribe]
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Posted on 03-28-11 11:46 PM     [Snapshot: 3095]     Reply [Subscribe]
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 Namaste!!

Need some help to seperate this file in (.h) and (.cpp) file.

thanks in advance

#ifndef EmployeeClass
#define EmployeeClass
#include <cstring>
 
const int DEFAULT_SIZE = 51;
 
class EmployeeData
{
private:
char *name;
int idnumber;
char *department;
char *position;
 
//private member function
void createName(int size, char *value)
{//Allocate the default amount of memory for name
name = new char [size];
 
//store a value in the memory
strcpy(name, value);}
 
void createDepartment(int size, char *value2)
{
department = new char [size];
strcpy(department, value2);}
 
void createPosition(int size, char *value3)
{
position = new char [size];
strcpy(position, value3);}
 
public:
//Constructor #1
EmployeeData()
{//Store an empty string in the name attribute.
createName(DEFAULT_SIZE, "");
createDepartment(DEFAULT_SIZE, "");
createPosition(DEFAULT_SIZE, "");
 
//initialize idnumber department position
idnumber = 0;}
 
//Constructor #2
EmployeeData(char *nam, char *dep, char *pos)
{//allocate memory and store the description.
createName(strlen(nam), nam);
createDepartment(strlen(dep), dep);
createPosition(strlen(pos), pos);
 
//initialize idnumber department position
idnumber = 0;}
 
//Constructor #3
EmployeeData(char *nam, int id, char *dep, char *pos)
{//Allocate memory and store the description.
createName(strlen(nam), nam);
createDepartment(strlen(dep), dep);
createPosition(strlen(pos), pos);
 
//Assign values to id deparment position
idnumber = id;}
 
//Destructor
~EmployeeData()
{ delete[] name;}
 
//mutator functions
void setName(char *n)
{strcpy(name, n);}
 
void setIdnumber(int id)
{idnumber = id;}
 
void setDepartment(char *d)
{strcpy (department,d);}
 
void setPosition(char *p)
{strcpy (position,p);}
 
//Accessor functions
const char *getName() const
{return name;}
 
int getIdnumber() const
{return idnumber;}
 
char *getDepartment() const
{return department;}
 
char *getPosition() const
{return position;}
};
#endif

 
Posted on 03-29-11 12:33 PM     [Snapshot: 3168]     Reply [Subscribe]
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Namaste!!!
 
Calling all c++ programmer
Need some help to seperate this file in (.h) and (.cpp) file.

thanks in advance

#ifndef EmployeeClass
#define EmployeeClass
#include <cstring>
 
const int DEFAULT_SIZE = 51;
 
class EmployeeData
{
private:
char *name;
int idnumber;
char *department;
char *position;
 
//private member function
void createName(int size, char *value)
{//Allocate the default amount of memory for name
name = new char [size];
 
//store a value in the memory
strcpy(name, value);}
 
void createDepartment(int size, char *value2)
{
department = new char [size];
strcpy(department, value2);}
 
void createPosition(int size, char *value3)
{
position = new char [size];
strcpy(position, value3);}
 
public:
//Constructor #1
EmployeeData()
{//Store an empty string in the name attribute.
createName(DEFAULT_SIZE, "");
createDepartment(DEFAULT_SIZE, "");
createPosition(DEFAULT_SIZE, "");
 
//initialize idnumber department position
idnumber = 0;}
 
//Constructor #2
EmployeeData(char *nam, char *dep, char *pos)
{//allocate memory and store the description.
createName(strlen(nam), nam);
createDepartment(strlen(dep), dep);
createPosition(strlen(pos), pos);
 
//initialize idnumber department position
idnumber = 0;}
 
//Constructor #3
EmployeeData(char *nam, int id, char *dep, char *pos)
{//Allocate memory and store the description.
createName(strlen(nam), nam);
createDepartment(strlen(dep), dep);
createPosition(strlen(pos), pos);
 
//Assign values to id deparment position
idnumber = id;}
 
//Destructor
~EmployeeData()
{ delete[] name;}
 
//mutator functions
void setName(char *n)
{strcpy(name, n);}
 
void setIdnumber(int id)
{idnumber = id;}
 
void setDepartment(char *d)
{strcpy (department,d);}
 
void setPosition(char *p)
{strcpy (position,p);}
 
//Accessor functions
const char *getName() const
{return name;}
 
int getIdnumber() const
{return idnumber;}
 
char *getDepartment() const
{return department;}
 
char *getPosition() const
{return position;}
};
#endif
 

 
Posted on 03-29-11 4:59 PM     [Snapshot: 3200]     Reply [Subscribe]
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i have a js issue,
i have this code ,

 stepForm.find   ('select.joined-date').bind('change', function () {
        var set = $('select.joined-date[rel="'+$(this).attr('rel')+'"]'),
            jMonth = set.filter('.month'),
            jDay = set.filter('.day'),
            jYear = set.filter('.year'),
            month = parseInt(jMonth.val()),
            day = parseInt(jDay.val()),
            year = parseInt(jYear.val()),
            date = (new Date()),
            // Is the coming february in a leap year?
            leap = date.getMonth() >= 1? (((year+1)%4)==0) : ((year%4)==0),
            dateText = ',
            yearText = ',
            days=30,
            future = jMonth.data('maxDaysFuture') || 365;

        if (!day) dateText = jDay.find('option:first').html();
        if (!year) yearText = jYear.find('option:first').html();
       
        if (!month) return;
        date.setDate(1);
        date.setMonth(month);
        date.setDate(0);
        var days = date.getDate();
       
        jDay.children().remove();
        if (dateText) jDay.append($('<option>').val(').html(dateText).attr('selected', false));       
        for (i=1; i<=days; i++) jDay.append($('<option>').val(i).html(i).attr('selected', day==i));
       
        if (!day) return;
        date.setDate(1);
        date.setMonth(month-1);
        date.setDate(day);
       
        if (date.getTime() < (new Date()).getTime())
            date.setFullYear(date.getFullYear()+1);
        minyear = date.getFullYear();
        date.setDate(date.getDate()+future);
        maxyear = date.getFullYear();
        jYear.children().remove();
        new Option(yearText, ', false)
       
        if (yearText) jYear.append($('<option>').val(').html(yearText).attr('selected', false));
       
        jYear.append($('<option>').val(minyear).html(minyear).attr('selected', year==minyear));
    });

what this code is doing is when user selects a month in a date drop down, it adds number of days in day dropdown,
now i want just a opposite of what it is there,
if  a user selects a day then a month should be appended in month field..
:/
how to do that

 
Posted on 03-29-11 5:23 PM     [Snapshot: 3211]     Reply [Subscribe]
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@nyshangal

do u know jquery? code is pretty much jquery?
just play around with the conditions, it is not that difficult.
i can help to make u understand jquery codes.


 
Posted on 03-29-11 7:51 PM     [Snapshot: 3227]     Reply [Subscribe]
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I know little bit of jquery but not much :(

 
Posted on 03-31-11 3:40 PM     [Snapshot: 3272]     Reply [Subscribe]
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 Namaste!!!
Hey guys!!!

Need some help in c sharp!!!!

 A program that create two dimensional array with 10 rows and 2 columns. The first comlumn should be filled with 10 random numbers between 0 and 100. The second column should contain the squared value of the element found in comun 1. 


thanks in advance1111

 
Posted on 04-05-11 9:12 PM     [Snapshot: 3357]     Reply [Subscribe]
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job hiring (software developers with H1b sponsorship)

http://www.cytiva.com/wgen/details.asp?wgen1357

 



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